Found my notes... Trying to reconstruct.
Beam diameter is (0.61*[distance to target in m]*[wavelength in m]/([lens diameter in m]/2))*2
So a 1m lens firing hard x-ray beam at a target 17,000 miles away makes a 0.33m diameter spot.
A 250MJ hard X-ray laser fired from this aperture gives...
[beam power in watts]/π*([distance to target in m]*Tan([Theta]/2))^2)
Theta = 1.22*[wavelength in m]/([lens diameter in m]/2)
So... our 250mJ laser at 17k miles, firing a 1 second pulse is putting out 2851.46 MW/m2/sec
Put another way, that's dropping 250MW on a 0.33m diameter circle.
That's enough to vaporize 1.87" of steel that diameter.
In GURPS terms 17,000 miles is the 1/2D distance and the 130.97 points of damage represented by the penetration aligns with the 5dx50(2) burn damage given.
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